00:01
The question says to find enthalpy change here.
00:07
Anthropy change.
00:12
So let's see the explanation for it.
00:17
First of all, we will see for the first equation, which is, i will write here equation first.
00:23
It is c12 s -22 -o -11 plus 12 -o -2, which forms product 12 -c -o -2 plus 11 s -2.
00:35
The value of dlh for this reaction is minus 5 -6 -40 kilojoul.
00:41
If you see for the equation 2, what is the equation 2 here? it is c6h12.
00:49
06 plus 6o2 which forms 6 co2 plus 6h2 and what is the value of dlh for this reaction? it is minus 2 800 kilojoule.
01:02
If we reverse this reaction then the value of dlh the sign will change here.
01:08
If equation 2 is reversed then it's sign will change.
01:21
So now we will get an equation three equation three will be 12 c -o -2 plus 12 s2 -2 -12 -0 which will form 2c6 s12 o6 plus 12 o2.
01:37
Here it is 12 o2...