00:01
So here in this question we are given a cantilever beam which is subjected to the forces which is shown here.
00:08
So this is the cantilever beam.
00:12
So let's say this is the point b from here which is subjected to a 10 kilo newton force.
00:21
So 10 kilo newton force and the distance from the point to the point b is 0 .5 meter.
00:27
Now here is a point c where a force of 15 kilo newton is acting and the distance between the point b and c is 1 meter.
00:38
And here this is the point d where a force of 35 kilo newton is acting and the distance between the c and d is 1 .5 meter.
00:48
So from here initially all the individual effect of the each forces are calculated.
00:54
So we are given the value of ei that is equal to 55 .3 multiplied by 10 raised to the power 6 newton per meter square.
01:04
Now we have to find out the deflection and the slop due to the concentration load of 35 kilo newton.
01:14
So y of d1 from here becomes equal to w of l raised to the power 3 divided by the 3 of e1.
01:20
Plugging to the value that is 35000 multiplied by the 0 .5 plus 1 plus 1 .5 raised to the power 3 which is divided by the 3 multiplied by the e1.
01:32
Length is basically the whole length which is divided in the partitions here.
01:36
So 3 multiplied by the 55 .3 multiplied by the 10 raised to the power 6.
01:43
So solving this term from here we get the value of y of d1 that is equal to 5 .696 millimeter.
01:51
Now we need to find out the value of theta d1 that is equal to w of l2 divided by the 2 of e1.
01:58
Ei plugging to the value again that is 35000 multiplied by the 0 .5 plus 1 plus 1 .5 raised to the power 2 which is divided by the 2 multiplied by the 55 .3 multiplied by the 10 raised to the power 6.
02:16
So the value of theta of d1 from here becomes equal to 2 .848 multiplied by the 10 raised to the power minus 3 radian.
02:24
So this is the value of theta d1.
02:28
In the same way we have to find out the deflection and slope due to the 15 kilo newton load.
02:34
So this from here is yd2 is equal to w of a raised to the power 3 divided by the 3 of ei plus w of a raised to the power 2 divided by the 2 of ei multiplied by the l minus e.
02:48
And theta of d2 from here is given by the formula that is w of a raised to the power 2 divided by the 2 ei...