00:01
In order to answer this question, let's talk about harding -weber equilibrium.
00:03
According to hardingwayneberg, remember that p plus q is equal to 1, where p is the frequency of the dominant allele in the population, and q is the frequency of the recessive allele in the population.
00:13
Then you have that p -square plus 2pq and plus q -2 -q is equal to 1, where p -square is the frequency of individuals in the population that are homozygous dominant, 2 pq is the frequency of individuals in the population that are heterozygos, and qs what is the frequency of individuals in the population of the homozygous recessive.
00:31
So it says, t .i .s .d .s .d .c.
00:32
Disease is caused by a loss of function of mutations tidagin on chromosome 15 that then caused for lysosomal enzyme.
00:39
Tysac is inherited as an autosomal -glysis condition.
00:42
Okay.
00:43
So this is going to be the normal allele, and this one is going to be a tish allele.
00:52
It is among aachanasi use of central european ancestry about one in 3 ,600 children is born with a disease.
01:01
So practically this is going to be the frequency for people who have a disease.
01:06
It means for people that are homo -sego -rescessive.
01:10
So as you can see here, the frequency for homosexual -rescessive in the population is q -square.
01:14
So you have that 1 divided by 3 ,600 people, you want to be equal to q squared.
01:22
Okay? now, you're going to apply good square at both sides in order to get w for q...