A genetic experiment involving peas yielded one sample of offspring consisting of 400 green peas and 132 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What is the test statistic? z = [ ] (Round to two decimal places as needed.) What is the P-value? P-value = [ ] (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, ?. B. Reject the null hypothesis because the P-value is greater than the significance level, ?. C. Reject the null hypothesis because the P-value is less than or equal to the significance level, ?. D. Fail to reject the null hypothesis because the P-value is greater than the significance level, ?. What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that 23% of offspring peas will be yellow. B. There is not sufficient evidence to support the claim that less than 23% of offspring peas will be yellow. C. There is sufficient evidence to support the claim that less than 23% of offspring peas will be yellow. D. There is sufficient evidence to warrant rejection of the claim that 23% of offspring peas will be yellow.
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Identify the null hypothesis (H0) and alternative hypothesis (H1): H0: p = 0.23 (23% of offspring peas will be yellow) H1: p ≠ 0.23 (The proportion of yellow offspring peas is not 23%) Show more…
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