Question

Text: A mass of 8 kg is attached to a spring and allowed to hang in the Earth's gravitational field. The spring stretches 4.4 cm before it reaches its equilibrium position. If allowed to oscillate, what would be its frequency? 2.4 Hz, 1.2 Hz, 4.8 Hz, 3.6 x 10^-3 Hz.

Name: text a mass of 8 kg is attached to a spring and allowed to hang in the earths gravitational field the spring stretches 44 cm before it reaches its equilibrium position if allowed to oscillat 68476
Uploaded: 2022-06-15T04:05:42-08:00
Duration: 1 min 45 s
Channel: Ankur S
Description: text a mass of 8 kg is attached to a spring and allowed to hang in the earths gravitational field the spring stretches 44 cm before it reaches its equilibrium position if allowed to oscillat 68476

          Text: A mass of 8 kg is attached to a spring and allowed to hang in the Earth's gravitational field. The spring stretches 4.4 cm before it reaches its equilibrium position. If allowed to oscillate, what would be its frequency? 2.4 Hz, 1.2 Hz, 4.8 Hz, 3.6 x 10^-3 Hz.

Added by Catherine T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ankur S

06/15/2022

Step 1

The spring constant (k) can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. The formula for Hooke's Law is: F = -kx Where: F is the force Show more…

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Text: A mass of 8 kg is attached to a spring and allowed to hang in the Earth's gravitational field. The spring stretches 4.4 cm before it reaches its equilibrium position. If allowed to oscillate, what would be its frequency? 2.4 Hz, 1.2 Hz, 4.8 Hz, 3.6 x 10^-3 Hz.