00:01
Let's look at this f -fx.
00:02
First, we plug into successive integers to find the corresponding f -fx values.
00:10
So let's see f -of -0 equals to minus 1.
00:14
And f -of -1 equals to 9.
00:27
Okay? so we know that the solution is between 0 to 1.
00:31
Now let's use the bisection method.
00:35
So i have 0 plus 1 over 2 equals to 0 .5.
00:38
So let's find f of 0 .5.
00:48
So this equals to, okay, so this equals to 1 .22 is greater than 0 .0.
01:03
So we know the solution is between 0 .5 to 1.
01:06
Okay, so i think we need to apply the bisection method again.
01:11
So we have 0 .5 plus 1 over 2, which equals to 0 .75.
01:17
Let's plug 0 .75 back into the equation.
01:48
So this equals to, okay, which is greater than 0.
01:58
So we know the solution is between 0 .75 to 1.
02:04
Okay, use the applied the bi -section method again.
02:10
This is equals to 0 .875.
02:25
Okay, so f of 0 .7, sorry, 875 equals to 5 .434, which is also greater than 0.
03:08
So we know that the solution is between to 1, okay? apply the biosection method again.
03:38
This equals to, so let's plug in this.
03:46
I get 6 .99, which is also greater than 0.
04:25
So let's, okay, i think i go to the wrong direction, right? i think i go to the wrong direction.
04:49
Okay, i'm sorry, i have to erase this and i have to redo it again...