Question

Thermodynamics I - test IV - 2019.06.12 0.5 kg of air at $t_1 = 327$ °C and pressure $p_1 = 430$ kPa is present in a cylinder with a piston. The gas slowly expands with no friction to the temperature $t_2 = 0$ °C and pressure $p_2 = 60$ kPa (polytrophic process). Find the work, heat of the process and change of internal energy. The isentropic exponent and particular gas constant for air are equal to $\kappa = 1.4$ and $R = 287$ J/(kgK), respectively. Assume that the gas can be treated as ideal.

          Thermodynamics I - test IV - 2019.06.12
0.5 kg of air at $t_1 = 327$ °C and pressure $p_1 = 430$ kPa is present in a cylinder with a piston. The gas slowly
expands with no friction to the temperature $t_2 = 0$ °C and pressure $p_2 = 60$ kPa (polytrophic process). Find the
work, heat of the process and change of internal energy. The isentropic exponent and particular gas constant
for air are equal to $\kappa = 1.4$ and $R = 287$ J/(kgK), respectively. Assume that the gas can be treated as ideal.

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Thermodynamics I - test IV - 2019.06.12
0.5 kg of air at t1 = 327 °C and pressure p1 = 430 kPa is present in a cylinder with a piston. The gas slowly
expands with no friction to the temperature t2 = 0 °C and pressure p2 = 60 kPa (polytrophic process). Find the
work, heat of the process and change of internal energy. The isentropic exponent and particular gas constant
for air are equal to κ = 1.4 and R = 287 J/(kgK), respectively. Assume that the gas can be treated as ideal.

Added by Dylan A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Madhur L

08/08/2023

Step 1

- m = 0.50 kg - p1 = 430 kPa = 430 000 Pa - p2 = 60 kPa = 60 000 Pa - t1 = 327 °C → T1 = 327 + 273 = 600 K - t2 = 0 °C → T2 = 0 + 273 = 273 K - κ = γ = 1.4, R = 287 J/(kg·K) Show more…

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Texts: 0.5 kg of air at t=32°C and pressure p=430 kPa is present in a cylinder with a piston. The gas slowly expands with no friction to the temperature t=0°C and pressure p=60 kPa in a polytropic process. Find the work, heat of the process, and change of internal energy. The isentropic exponent and particular gas constant for air are equal to K=1.4 and R=287 J/kgK, respectively. Assume that the gas can be treated as ideal.

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