Question

Use equations (1.1.1 and 1.1.2) to determine the (1) absolute error and (2) percent error for a value of 4.422 g/cm³ determined for the density of titanium ( which the true density value is 4.506 g/cm³ 1. absolute error = (measured value - true value) = (4.422 g/cm³ - 4.506 g/cm³) = -0.184 g/cm³ 2. percent error = (absolute error)/(true value) \times 100% = (-0.184 g/cm³)/(4.506 g/cm³) \times 100% = -4.08% Question 1.1.5 In a series of experiments to determine the density of lead (Pb), the results in the second column of the table below were determined. Taking 11.343 g/ml to be the true value for the density of lead, complete the table by using equation (1.1.1) to calculate the absolute error and equation (1.1.2) to calculate the percent error for each density determination. Enter absolute error values in units of g/ml to the nearest 0.001 g/ml. Include the unit using the symbol g/ml. Enter percent error values to the nearest 0.01% without units and without the percent symbol. Results Determination Pb Density Analysis Absolute Error Percent Error 1 11.662 g/mL Number Units Number 2 11.441 g/mL Number Units Number 3 10.841 g/mL Number Units Number

          Use equations (1.1.1 and 1.1.2) to determine the (1) absolute error and (2) percent error for a value of 4.422 g/cm³ determined for the density of titanium (
which the true density value is 4.506 g/cm³
1. absolute error = (measured value - true value) = (4.422 g/cm³ - 4.506 g/cm³) = -0.184 g/cm³
2. percent error = (absolute error)/(true value) \times 100% = (-0.184 g/cm³)/(4.506 g/cm³) \times 100% = -4.08%
Question 1.1.5
In a series of experiments to determine the density of lead (Pb), the results in the second column of the table
below were determined. Taking 11.343 g/ml to be the true value for the density of lead, complete the table by using
equation (1.1.1) to calculate the absolute error and equation (1.1.2) to calculate the percent error for each density
determination.
Enter absolute error values in units of g/ml to the nearest 0.001 g/ml. Include the unit using the symbol g/ml.
Enter percent error values to the nearest 0.01% without units and without the percent symbol.
Results
Determination Pb Density
Analysis
Absolute Error
Percent Error
1
11.662 g/mL
Number
Units
Number
2
11.441 g/mL
Number
Units
Number
3
10.841 g/mL
Number
Units
Number

$Use equations (1.1.1 and 1.1.2) to determine the (1) absolute error and (2) percent error for a value of 4.422 g/cm³ determined for the density of titanium ( which the true density value is 4.506 g/cm³ 1. absolute error = (measured value - true value) = (4.422 g/cm³ - 4.506 g/cm³) = -0.184 g/cm³ 2. percent error = (absolute error)/(true value) ×100% = (-0.184 g/cm³)/(4.506 g/cm³) \times 100% = -4.08% Question 1.1.5 In a series of experiments to determine the density of lead (Pb), the results in the second column of the table below were determined. Taking 11.343 g/ml to be the true value for the density of lead, complete the table by using equation (1.1.1) to calculate the absolute error and equation (1.1.2) to calculate the percent error for each density determination. Enter absolute error values in units of g/ml to the nearest 0.001 g/ml. Include the unit using the symbol g/ml. Enter percent error values to the nearest 0.01% without units and without the percent symbol. Results Determination Pb Density Analysis Absolute Error Percent Error 1 11.662 g/mL Number Units Number 2 11.441 g/mL Number Units Number 3 10.841 g/mL Number Units Number$

Added by Brian Z.

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