00:01
Hello, we have u is equal to this vector, v equal to this vector and u cross v is equal to the cross product of u and v is equal to i j k times i j k minus 2 minus 2 minus 3 5 5.
00:30
So, to find the cross product of these two vectors, we take the determinant of this matrix, which is equal to i times minus 2 times 3 is minus 6 minus minus 3 times 5 is minus 15.
00:47
So, minus 6 minus minus 15 is minus 6 plus 15, which is minus 6, which is equal to 9 minus 6 plus 15, which is equal to 9.
01:01
So, we have 9 i plus j times minus 3 5 is minus 15 minus minus 2 3, which is minus minus 6.
01:13
So, minus 15 plus 6, which is minus 9 plus k times minus 2 5, which is minus 10 minus minus 2 5, which is minus 10.
01:28
So, minus 10 minus minus 10, which is minus 10 plus 10.
01:33
So, minus 10 plus 10 is 0.
01:36
So, this vector is 9 i minus 9 j.
01:51
Okay, so we find u cross v is the vector 9 i minus 9 j...