Question

2. (12 points) Consider the function $f(x)$ whose graph is given below. y 6 5 4 f(x) 3 2 1 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 x -1 -2 -3 Determine the following limits or values. Write DNE if a limit does not exist. (2 points each) (a) $\lim_{x \to -3^-} f(x) = 3$ (b) $\lim_{x \to -3^+} f(x) = 1$ (c) $\lim_{x \to -3} f(x) = 1$ (d) $\lim_{x \to -7} f(x) = 2$ (e) $f(-7) = 3$ (f) $f(5) = DNE$

          2. (12 points) Consider the function $f(x)$ whose graph is given below.
y
6
5
4
f(x)
3
2
1
-8 -7 -6 -5 -4 -3 -2 -1
1
2
3
4
5
6
7
8
x
-1
-2
-3
Determine the following limits or values. Write DNE if a limit does not exist. (2 points each)
(a) $\lim_{x \to -3^-} f(x) = 3$
(b) $\lim_{x \to -3^+} f(x) = 1$
(c) $\lim_{x \to -3} f(x) = 1$
(d) $\lim_{x \to -7} f(x) = 2$
(e) $f(-7) = 3$
(f) $f(5) = DNE$

2. (12 points) Consider the function f(x) whose graph is given below.
y
6
5
4
f(x)
3
2
1
-8 -7 -6 -5 -4 -3 -2 -1
1
2
3
4
5
6
7
8
x
-1
-2
-3
Determine the following limits or values. Write DNE if a limit does not exist. (2 points each)
(a) limx → -3^- f(x) = 3
(b) limx → -3^+ f(x) = 1
(c) limx → -3 f(x) = 1
(d) limx → -7 f(x) = 2
(e) f(-7) = 3
(f) f(5) = DNE

Added by Natalie H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Suman Saurav Thakur

02/07/2022

Step 1

From the graph, we can see that as x approaches -3 from the left, the value of f(x) approaches 3. Show more…

Show all steps

Thanks for your feedback!

Texts: (12 points) Consider the function f(x) whose graph is given below. Determine the following limits or values. Write DNE if a limit does not exist. (2 points each) (a) lim_(x->-3^(-))f(x)=3 (b) lim_(x->-3^(+))f(x)=1 (c) lim_(x->-3)f(x)=1 (d) lim_(x->-7)f(x)=2 (e) f(-7)=3 (f) f'(5)=DNE 2. (12 points) Consider the function f(x) whose graph is given below. y 6 5 4 f(x) 3 2 1 2 T 18 7 +6 +5 +3 +2 +1 -1 2 Determine the following limits or values. Write DNE if a limit does not exist. (2 points each) (a) lim_(x->∞)f(x) = 3 (b) lim_(x->-∞)f(x) = DNE (c) lim_(x->3)f(x) = 1 (d) lim_(x->-1)f(x) = 2 (e) f(-7) = 3