Question

Solve, finding all solutions in $[0, 2\pi)$ or $[0^\circ, 360^\circ)$. $2\sin^2x + \sqrt{3}\sin x = 0$ The solution(s) in $[0^\circ, 360^\circ)$ is/are $x = $ (Type your answer in degrees. Do not include the degree symbol in your answer. Use a comma to separate answers as needed.) The solution(s) in $[0, 2\pi)$ is/are $x = $ (Simplify your answer. Type an exact answer, using $\pi$ as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)

          Solve, finding all solutions in $[0, 2\pi)$ or $[0^\circ, 360^\circ)$.
$2\sin^2x + \sqrt{3}\sin x = 0$
The solution(s) in $[0^\circ, 360^\circ)$ is/are $x = $
(Type your answer in degrees. Do not include the degree symbol in your answer. Use a comma to separate answers as needed.)
The solution(s) in $[0, 2\pi)$ is/are $x = $
(Simplify your answer. Type an exact answer, using $\pi$ as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)

$Solve, finding all solutions in [0, 2π) or [0^∘, 360^∘). 2sin^2x + √(3)sin x = 0 The solution(s) in [0^∘, 360^∘) is/are x = (Type your answer in degrees. Do not include the degree symbol in your answer. Use a comma to separate answers as needed.) The solution(s) in [0, 2π) is/are x = (Simplify your answer. Type an exact answer, using π as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)$

Added by Michelle P.

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