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Part one: Paging Use the provided page table to answer the following questions
Page size = 512
Logical address space = 4196
Page number
2
3
5
Frame number
3
7
0
The number of bits representing the page displacement (offset) is
If we have a logical address with a page number 3 and page offset 6, then the physical address is:
3. The frame size equals
4. If the physical address space = 4096, how many frames does it have?
5. If the logical address (375) is given, then the physical address is (
10
If the logical address (11100010110) is given, then the physical address is yt
Part Two: Segmentation
Answer the following questions after referring to the provided segment table
limit base 01000 1400 1 400 6300 2 400 4300 3 1100 3200 1000 4700
1. The logical address [3,1350] produces the physical address
2. The logical address [5,100] produces the physical address
3. The logical address [2,300] produces the physical address
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