Question

a) If $z = \frac{\lambda + 9i}{1 + \lambda i}$ and $z$ is a real number, find the possible value of $\lambda$ where $\lambda > 0$.

Name: a) If z = (λ + 9i)/(1 + λ i) and z is a real number, find the possible value of λ where λ > 0.
Uploaded: 2021-08-18T19:46:09-08:00
Duration: 3 min 55 s
Channel: Satyam Gupta
Description: a) If z = (λ + 9i)/(1 + λ i) and z is a real number, find the possible value of λ where λ > 0.

          a) If $z = \frac{\lambda + 9i}{1 + \lambda i}$ and $z$ is a real number, find the possible value of $\lambda$ where $\lambda > 0$.

Added by Michelle M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Satyam Gupta

08/18/2021

Step 1

This means that the imaginary part of z, bi, must be equal to 0. Show more…

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Texts: 2 + 9i, If z = a + bi and z is a real number, find the possible value of a where a > 0 for 1 + 1i.

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a) If $z = \frac{\lambda + 9i}{1 + \lambda i}$ and $z$ is a real number, find the possible value of $\lambda$ where $\lambda > 0$.

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