A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by $f(t) = -34t + 280$. The velocity of the ball 9 seconds after launch is feet/second. (Round answer to nearest tenth.)
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Step 1: We are given the velocity function of the ball, f(t) = -34t + 280, where t represents the time in seconds after the ball is launched. Show more…
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