00:01
So we are trying to find the solution set to this space such that we may find a basis in the dimension of that space.
00:08
To do this i'm going to write these equations as a matrix.
00:12
That's going to be 1 1 negative 1, great, negative 2 negative 1 2, and then for our last one we have negative 1 on x1, positive 1 on x3, 0 on x2.
00:24
If we use the first row to clear out the first column, we need to add two times the first row to the second row.
00:33
So 2 times 1 is 2 plus negative 2 is 0.
00:36
2 times 1 is 2 plus negative 1 is 1.
00:39
2 times negative 1 is negative 2 plus 2 is 0.
00:42
Then we need to add 1 times the first row to the last one.
00:45
1 times negative 1, 1 times is 1 plus 1 is 0.
00:49
1 times 1 is 1 plus 0 is 1.
00:52
1 times negative 1 is negative 1 plus 1 is 0.
00:57
And then that brings us now again, we can just clear out the last row with the second.
01:02
0 0 0...