Question

an equivalent double integral with the order of integration reversed. 16) \int_{10}^{15} \int_{25-x}^{15} dy dx A) \int_{10}^{5} \int_{15-y}^{5} dx dy C) \int_{10}^{15} \int_{25-y}^{15} dx dy volume of the indicated region. 7) the region bounded above by the sphere $x^2 + y^2 + z^2 = 25$ and below by the cone $z = \sqrt{x^2 + y^2}$ A) $\frac{125}{4} \pi (2 - \sqrt{2})$ C) $\frac{125}{4} \pi (2 - \sqrt{3})$ B) \int_{10}^{15} \int_{15-y}^{5} dx dy D) \int_{10}^{5} \int_{25-y}^{15} dx dy B) $\frac{125}{3} \pi (2 - \sqrt{3})$ D) $\frac{125}{3} \pi (2 - \sqrt{2})$

          an equivalent double integral with the order of integration reversed.
16) \int_{10}^{15} \int_{25-x}^{15} dy dx
A) \int_{10}^{5} \int_{15-y}^{5} dx dy
C) \int_{10}^{15} \int_{25-y}^{15} dx dy
volume of the indicated region.
7) the region bounded above by the sphere $x^2 + y^2 + z^2 = 25$ and below by the cone $z = \sqrt{x^2 + y^2}$
A) $\frac{125}{4} \pi (2 - \sqrt{2})$
C) $\frac{125}{4} \pi (2 - \sqrt{3})$
B) \int_{10}^{15} \int_{15-y}^{5} dx dy
D) \int_{10}^{5} \int_{25-y}^{15} dx dy
B) $\frac{125}{3} \pi (2 - \sqrt{3})$
D) $\frac{125}{3} \pi (2 - \sqrt{2})$

an equivalent double integral with the order of integration reversed.
16) ∫10^15 ∫25-x^15 dy dx
A) ∫10^5 ∫15-y^5 dx dy
C) ∫10^15 ∫25-y^15 dx dy
volume of the indicated region.
7) the region bounded above by the sphere x^2 + y^2 + z^2 = 25 and below by the cone z = √(x^2 + y^2)
A) (125)/(4)π (2 - √(2))
C) (125)/(4)π (2 - √(3))
B) ∫10^15 ∫15-y^5 dx dy
D) ∫10^5 ∫25-y^15 dx dy
B) (125)/(3)π (2 - √(3))
D) (125)/(3)π (2 - √(2))

Added by Joseph C.

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