Consider the subspace $H$ of $\mathbb{R}^4$ given by $H = \begin{Bmatrix} \begin{bmatrix} -a - 9b + 2c\\ 2a + 18b - 2c \\ -a - 9b + 4c \\ -a - 9b + 2c \end{bmatrix} : a, b, c \in \mathbb{R} \end{Bmatrix}$ a. Find a basis for $H$. (Note: Use one vector per answerbox. It's okay if some of the answerboxes remain empty.) $\{ \Box, \Box, \Box \}$ Why am I not getting partial credit? b. State the dimension of $H$. dim(H) = \Box
Added by Alexis M.
Close
Step 1
Step 1: First, let's write down the general form of the vectors in the subspace \(H\) as given: \[H = \{(-a-9b+2c, 2a+18b-2c, -a-9b+4c, -a-9b+2c) | a, b, c \in \mathbb{R}\}\] Show more…
Show all steps
Your feedback will help us improve your experience
Maitreya E and 84 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Let H be the set of all vectors of the form [s, 3s, 2s]. Find a vector in R3 such that H = Span{v}. Why does this show that H is a subspace of R3?
Sri K.
Find the dimension of the subspace H of R2 spanned by [[],[][]] dim H=
Zhumagali S.
Show that H is not a subspace of R because the two vectors are not closed under addition. H is also not closed under scalar multiplication.
Madhur L.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD