Question

Let \(\vec{u} = \langle 2, -3, 7 \rangle\) and \(\vec{v} = \langle 7, -2, 1 \rangle\). Compute the following: \(\vec{u} \cdot \vec{v} = 27\) \(\vec{v} \cdot \vec{u} = 27\) \(||\vec{u}||^2 = 62\) \(10(\vec{u} \cdot \vec{v}) = 270\) \((10\vec{u}) \cdot \vec{v} = 270\) \(\vec{u} \cdot (10\vec{v}) = 270\) \((\vec{u} \cdot \vec{v})\vec{v} = \text{DNE}\)

          Let \(\vec{u} = \langle 2, -3, 7 \rangle\) and \(\vec{v} = \langle 7, -2, 1 \rangle\).
Compute the following:
\(\vec{u} \cdot \vec{v} = 27\)
\(\vec{v} \cdot \vec{u} = 27\)
\(||\vec{u}||^2 = 62\)
\(10(\vec{u} \cdot \vec{v}) = 270\)
\((10\vec{u}) \cdot \vec{v} = 270\)
\(\vec{u} \cdot (10\vec{v}) = 270\)
\((\vec{u} \cdot \vec{v})\vec{v} = \text{DNE}\)

Let u⃗ = ⟨ 2, -3, 7 ⟩ and v⃗ = ⟨ 7, -2, 1 ⟩.
Compute the following:
u⃗·v⃗ = 27
v⃗·u⃗ = 27
||u⃗||^2 = 62
10(u⃗·v⃗) = 270
(10u⃗) ·v⃗ = 270
u⃗· (10v⃗) = 270
(u⃗·v⃗)v⃗ = DNE

Added by David M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Nishant Tyagi

05/01/2021

Step 1

To compute 2√27, we need to find the square root of 27 and then multiply it by 2. The square root of 27 is √27 = 3√3. Multiplying it by 2, we get 2√27 = 2 * 3√3 = 6√3. Show more…

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Texts: Could you do the question in red? Let u = 2 - 3, 7 and = 7, -2, 1 Compute the following: a. 2√27 b. 1√27 c. 1/3/12 d. 62 e. 10(u = 270 f. 10 = 270 g. u.(10) h. 270 i. u. = DNE j. X Submit Question