00:01
So in this question, we say we want to find the values of x for which this series converges, and we'll enter our answer using integral notation.
00:10
Here i have the sum from an equals 0 to infinity of the quantity of x minus 6 being raised to the n power, divided by 4 to the n power.
00:22
Now, what i would notice is that this is in fact a geometric series.
00:27
You could say, this is the sum from n equals 0 to infinity of the quantity of x minus 6 over 4, that quantity raised to the power of n.
00:45
Now, i know that a geometric series converges whenever the absolute value of r is less than 1.
00:58
Now, what is my r value this time? my r value is x minus 6 over 4.
01:07
So this is going to converge whenever the absolute value of x minus 6 over 4 is less than 1.
01:17
Breaking this out of my absolute value bars, we have negative 1 is less than x minus 6 over 4, which is less than 1.
01:31
Multiplying through by 4 gives you negative 4 is less than x minus 6 is less than 4.
01:40
And adding 6 gives you 2 is less than x is less than 10.
01:47
Unfortunately, they said i need interval notation.
01:52
That's inequality notation...