Question

Given a particle moving according to $s(t) = \sqrt{t}(3t^2 - 35t + 90)$: (A) Find the velocity function. (B) What is the velocity after 3 seconds? (C) When is the particle at rest? (List the smaller answer first.) (D) Find the total distance traveled during the first 8 seconds. (Hint: When is the particle traveling in the positive direction?) (A) $v(t) = \boxed{} ft/s$ (B) $v(3) = \boxed{} ft/s$ (C) $t = \boxed{} s$ and $t = \boxed{} s$ (D) distance $= \boxed{} ft$

          Given a particle moving according to $s(t) = \sqrt{t}(3t^2 - 35t + 90)$:
(A) Find the velocity function.
(B) What is the velocity after 3 seconds?
(C) When is the particle at rest? (List the smaller answer first.)
(D) Find the total distance traveled during the first 8 seconds. (Hint: When is the particle traveling in the positive direction?)
(A) $v(t) = \boxed{} ft/s$
(B) $v(3) = \boxed{} ft/s$
(C) $t = \boxed{} s$ and $t = \boxed{} s$
(D) distance $= \boxed{} ft$

Given a particle moving according to s(t) = √(t)(3t^2 - 35t + 90):
(A) Find the velocity function.
(B) What is the velocity after 3 seconds?
(C) When is the particle at rest? (List the smaller answer first.)
(D) Find the total distance traveled during the first 8 seconds. (Hint: When is the particle traveling in the positive direction?)
(A) v(t) = ft/s
(B) v(3) = ft/s
(C) t = s and t = s
(D) distance = ft

Added by Yolanda B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Gregory Higby

03/20/2023

Step 1

Step 1: To find the velocity function, we need to take the derivative of the position function with respect to time. Show more…

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Texts: Given a particle moving according to s(t) = V/t(3t^2 - 35t + 90): (A) Find the velocity function. (B) What is the velocity after 3 seconds? (C) When is the particle at rest? (List the smaller answer first.) (D) Find the total distance traveled during the first 8 seconds. (Hint: When is the particle traveling in the positive direction?) (A) v(t) ft/s (B) v(3) ft/s (C) t = pue (D) distance = ft