Texts: Given P = (0, 1, -1), Q = (2, 1, 0), R = (3, -1, 0). (a) Find the equation ax + by + cz = d, of the plane through these points. (b) Is the line x = 2 + t, y = 3 - 2t, z = 5 - t parallel to the plane you found in part (a)?
Added by Elizabeth G.
Step 1
To find the equation of a plane, we need to find its normal vector. The normal vector is perpendicular to the plane and can be found by taking the cross product of two vectors in the plane. Let's take two vectors in the plane: PQ and PR. PQ = Q - P = (2, 1, 0) - Show more…
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