Question

Given two revenue models (in millions of dollars) for a large corporation, where both models are estimates of revenues from 2015 through 2040 and \(t = 0\) corresponds to the beginning of 2015. \(R = 6.11 + 0.33t + 0.06t^2\) \(R = 6.11 + 0.16t + 0.01t^2\) Hints: Sketch a graph of the 2 functions, also think about the definition of time carefully along with the time period asked for below. Which model predicts the greater revenue? \(R = 6.11 + 0.33t + 0.06t^2\) \(R = 6.11 + 0.16t + 0.01t^2\) How much more revenue does that greater revenue model predict over the 6 year period from 2021 through 2026? (Round your answer to three decimal places.) 7.920 millions of dollars

          Given two revenue models (in millions of dollars) for a large corporation, where both models are estimates of revenues from 2015 through 2040 and \(t = 0\) corresponds to the beginning of 2015.
\(R = 6.11 + 0.33t + 0.06t^2\)
\(R = 6.11 + 0.16t + 0.01t^2\)
Hints: Sketch a graph of the 2 functions, also think about the definition of time carefully along with the time period asked for below.
Which model predicts the greater revenue?
\(R = 6.11 + 0.33t + 0.06t^2\)
\(R = 6.11 + 0.16t + 0.01t^2\)
How much more revenue does that greater revenue model predict over the 6 year period from 2021 through 2026?
(Round your answer to three decimal places.)
7.920 millions of dollars

Given two revenue models (in millions of dollars) for a large corporation, where both models are estimates of revenues from 2015 through 2040 and t = 0 corresponds to the beginning of 2015.
R = 6.11 + 0.33t + 0.06t^2
R = 6.11 + 0.16t + 0.01t^2
Hints: Sketch a graph of the 2 functions, also think about the definition of time carefully along with the time period asked for below.
Which model predicts the greater revenue?
R = 6.11 + 0.33t + 0.06t^2
R = 6.11 + 0.16t + 0.01t^2
How much more revenue does that greater revenue model predict over the 6 year period from 2021 through 2026?
(Round your answer to three decimal places.)
7.920 millions of dollars

Added by Mohamed W.

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