00:01
Hey there, welcome to numerate.
00:03
So we are given the tire lifetimes of an automobile.
00:07
So with that, the lifetimes are normally distributed as given, and we are given the population mean and standard deviation.
00:15
And we had to find the following probabilities and proportions.
00:19
So with this, we're going to do a first.
00:25
So a, we have, what is the probability that i randomly selected tire has lifetime greater than 48? so with our given mean and standard deviation, let's write it down first.
00:39
Population mean is denoted as mule, which is 39, and we have our population standard deviation, which is denoted sigma here, which is basically 4.
00:56
So our probability we're looking for for part a is p of x is greater than 48 would be our probability function here.
01:09
All right, p of x is greater than 48.
01:13
We will have to calculate our z square heritude in order to find a probability.
01:18
Z equals x values of 48, minus our mean 39, divided by our standard deviation, 4.
01:28
We're going to calculate this and see what value we get.
01:32
And you should end up a value of 2 .25.
01:36
Now, to find a probability, you can use a z -score probability table, or you can use a calculator.
01:44
So, but you should get a probability of around 0 .01 to 2.
01:53
Right, rounded to four decimal places here.
01:56
Let me see.
01:57
Yep, four decimal places.
02:02
All right.
02:03
And then let's do part b.
02:05
So part b says, what's the proportion of tires that have lifetimes between 38 and 43? so that proportion, we still denoted as probability, where x is between 38, and 43...