Question

S? and S? are closed for a long time. Find the currents $I_3$ and the charge $Q$ on the capacitor at steady state. $R_1 = 2R$, $R_2 = R/2$ A) $I_3 = \frac{\varepsilon}{2R}$, $Q = \frac{\varepsilon C}{2}$ B) $I_3 = \frac{\varepsilon}{4R}$, $Q = \frac{\varepsilon C}{4}$ C) $I_3 = \frac{2\varepsilon}{5R}$, $Q = \frac{4\varepsilon C}{5}$ D) $I_3 = \frac{2\varepsilon}{5R}$, $Q = \frac{\varepsilon C}{5}$ E) $I_3 = \frac{\varepsilon}{2R}$, $Q = \frac{\varepsilon C}{4}$

          S? and S? are closed for a long time. Find the currents $I_3$ and the charge $Q$ on the capacitor at steady state. $R_1 = 2R$, $R_2 = R/2$
A) $I_3 = \frac{\varepsilon}{2R}$, $Q = \frac{\varepsilon C}{2}$
B) $I_3 = \frac{\varepsilon}{4R}$, $Q = \frac{\varepsilon C}{4}$
C) $I_3 = \frac{2\varepsilon}{5R}$, $Q = \frac{4\varepsilon C}{5}$
D) $I_3 = \frac{2\varepsilon}{5R}$, $Q = \frac{\varepsilon C}{5}$
E) $I_3 = \frac{\varepsilon}{2R}$, $Q = \frac{\varepsilon C}{4}$

S? and S? are closed for a long time. Find the currents I3 and the charge Q on the capacitor at steady state. R1 = 2R, R2 = R/2
A) I3 = (ε)/(2R), Q = (ε C)/(2)
B) I3 = (ε)/(4R), Q = (ε C)/(4)
C) I3 = (2ε)/(5R), Q = (4ε C)/(5)
D) I3 = (2ε)/(5R), Q = (ε C)/(5)
E) I3 = (ε)/(2R), Q = (ε C)/(4)

Added by Roger M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Rachel Gore

06/07/2023

Step 1

This means that the capacitor has been charged to its maximum capacity and is fully charged. In this state, the current through the circuit is zero (Iz = 0) and the charge on the capacitor is also zero (Q = 0). Show more…

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Texts: S1 and S2 are closed for a long time. Find the currents Iz and the charge Q on the capacitor at steady state. R=2R, R=R/2 S1: A) Iz = 0 Q = 0 S2: A) Iz = 33/2R Q = 4C/5R E) Iz = 2R