00:01
The triangular loop of wire shown in the drawing carries a current eye and the uniform magnetic field is parallel to ab as shown over here and it has this much of mind.
00:10
So what is the magnetic force exerted on each side of the triangle and magnitude of the net force.
00:15
We know that the magnetic force is given by i times l cross b on a wire.
00:21
This is definitely the cross product.
00:23
So if we talk about ab, remember that ab the current is like this and the magnetic field is like this.
00:29
So angle between them is what 180, right? so when we drew sign of 180 and we know that sign 180 is zero.
00:35
So the force on a .b.
00:38
For ac, i know that they are at 90 degrees because the current is over here and the magnetic field is over here.
00:44
So it will just be i -l -b sign of 90 and sign 90 is one.
00:48
So all we have to do is plug in the current.
00:50
Plug in the length.
00:52
What is the length of the? okay, so the length is not given.
00:55
That's where they want us to do some math over here.
00:59
Because the triangle is given and this angle is given.
01:01
Let's say this length is l1 and this length is l2.
01:07
So for l1, we know that we can use tan of theta, because tan of 55 is going to be opposite l1 over adjacent 2.
01:15
So the value of l1 is 2 tan 55 degrees...