00:01
So this is the proposition.
00:04
So for all x, we have p of x, this janitor, k of x.
00:11
It's not equivalent to, for ox, p of x, this janitor for ox, k of x.
00:19
So i'm going to use a counter example to explain or to arrive at this.
00:27
No, not equivalent.
00:28
So you are going to let p of x to be p of x to be x to be x minus 1 which is equal to 0.
00:45
And you are going to get a we are going to let kill of x to be x minus 2 is equal to 0.
00:59
And we have vu which is equal to d.
01:03
Having this domain, we have 1.
01:06
And 2.
01:11
So it means p of 1 is true...