Question

Use the definite integral to find the area between the x-axis and f(x) over the indicated interval. Check first to see if the graph crosses the x-axis in the given interval.\ f(x) = 3x^2; [-1, 3]\ The area between the x-axis and f(x) is $\frac{123}{2}$. (Simplify your answer.)

Name: Use the definite integral to find the area between the x-axis and f(x) over the indicated interval. Check first to see if the graph crosses the x-axis in the given interval.f(x) = 3x^2; [-1, 3]The area between the x-axis and f(x) is (123)/(2). (Simplify your answer.)
Uploaded: 2022-05-09T10:41:18-08:00
Duration: 3 min 51 s
Channel: Ahmet Yavas
Description: Use the definite integral to find the area between the x-axis and f(x) over the indicated interval. Check first to see if the graph crosses the x-axis in the given interval.f(x) = 3x^2; [-1, 3]The area between the x-axis and f(x) is (123)/(2). (Simplify your answer.)

          Use the definite integral to find the area between the x-axis and f(x) over the indicated interval. Check first to see if the graph crosses the x-axis in the given interval.\
f(x) = 3x^2; [-1, 3]\
The area between the x-axis and f(x) is $\frac{123}{2}$. (Simplify your answer.)

Use the definite integral to find the area between the x-axis and f(x) over the indicated interval. Check first to see if the graph crosses the x-axis in the given interval.f(x) = 3x^2; [-1, 3]The area between the x-axis and f(x) is (123)/(2). (Simplify your answer.)

Added by Stanley G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ahmet Yavas

05/09/2022

Step 1

To do this, we can find the values of f(x) at the endpoints of the interval. When x = 1, f(1) = 3(1)^3 = 3(1) = 3. When x = 3, f(3) = 3(3)^3 = 3(27) = 81. Since f(1) = 3 and f(3) = 81, and both values are positive, the graph of f(x) does not cross the x-axis in Show more…

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Texts: Use the definite integral to find the area between the x-axis and f(x) over the indicated interval. Check first to see if the graph crosses the x-axis in the given interval. f(x) = 3x^3, [1,3] The area between the x-axis and f(x) is 2.