Question

1. The volume change on mixing for liquid methyl formate (1) + liquid ethanol (2) system at 298.15 K may be approximately represented by the: $\Delta V_{mixing} = 0.8x_1x_2$ (a) Using the correlation and the data V1=67.28 cm3/mol, V2=58.68 cm3/mol, determine the molar volume of the mixture at x1=0.6 (b) Using the above data and correlations, determine the expression for the partial molar excess volume for component 1 & 2. Answer: (a) 64.032 cm$^3$/mol (b) $\bar{V}^E_1 = 0.8x_2^2$ $\bar{V}^E_2 = 0.8x_1^2$

          1. The volume change on mixing for liquid methyl formate (1) + liquid ethanol
(2) system at 298.15 K may be approximately represented by the:
$\Delta V_{mixing} = 0.8x_1x_2$
(a) Using the correlation and the data V1=67.28 cm3/mol, V2=58.68 cm3/mol,
determine the molar volume of the mixture at x1=0.6
(b) Using the above data and correlations, determine the expression for the partial
molar excess volume for component 1 & 2.
Answer: (a) 64.032 cm$^3$/mol
(b) $\bar{V}^E_1 = 0.8x_2^2$  $\bar{V}^E_2 = 0.8x_1^2$

1. The volume change on mixing for liquid methyl formate (1) + liquid ethanol
(2) system at 298.15 K may be approximately represented by the:
Δ Vmixing = 0.8x1x2
(a) Using the correlation and the data V1=67.28 cm3/mol, V2=58.68 cm3/mol,
determine the molar volume of the mixture at x1=0.6
(b) Using the above data and correlations, determine the expression for the partial
molar excess volume for component 1 2.
Answer: (a) 64.032 cm^3/mol
(b) V̅^E1 = 0.8x2^2 V̅^E2 = 0.8x1^2

Added by Kevin R.

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