T/F 1. Let $A = \begin{bmatrix} 2 & 3 \\ 1 & 4 \end{bmatrix}$, then $A^{-1} = \frac{1}{5} \begin{bmatrix} 2 & -3 \\ -1 & 4 \end{bmatrix}$. 2. For any $2 \times 2$ matrices A and B, AB = BA. 3. $\begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix} \begin{bmatrix} 1 & 2 \\ 4 & 5 \end{bmatrix} = \begin{bmatrix} -3 & -3 \\ 8 & 10 \end{bmatrix}$. 4. Let $A = \begin{bmatrix} 1 & 0 \\ 0 & 2 \end{bmatrix}$, $B = \begin{bmatrix} -1 & 0 \\ 0 & 1 \end{bmatrix}$ then A and B commute. 5. $\begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix} \begin{bmatrix} 1 & -1 & 1 \end{bmatrix} = 2$.
Added by Stephanie S.
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If A = 1, then A^-1 = 1^-1 = 1. The inverse of 1 is still 1, not 2. So the statement A^-1 = 2 is incorrect. Show more…
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