Question

Sol? Given that the depth of flow ranges 0.6 m < H < 0.9 m. ? Considering => H = (0.6 + 0.9) / 2 = 0.75 m Now verify the equation & above consideration Q = S??? (BH)?/3 / r (B+2H)%/3 => 0.0002??? × (20 × 0.75)?/3 / 0.03 × (20 + 2 × 0.75)%/3 => 5.67 m3/sec Now, Considering a slightly less depth. => (0.6 + 0.75) / 2 = 0.675 m Q = 0.0002??? (20 × 0.675)?/3 / 0.03 × (20 + 2 × 0.675)%/3 = 4.74 m3/sec Now, A new depth b/w 0.675 & 0.75 m Avg of depth will be = (0.675 + 0.75) / 2 = 0.7125 m Q = 0.0002??? × (20 × 0.7125)?/3 / 0.3 × (20 + 2 × 0.7125)%/3 => 0.014 × 84.5 / 0.03 × 7.55 => 5.22 m3/sec Now, Taking Avg depth b/w 0.675 & 0.7125 => (0.675 + 0.7125) / 2 = 0.69375 Q = 0.14 × (20 × 0.69375)?/3 / 0.03 × (20 + 2 × 0.69375)%/3 => 4.90 m3/sec Now Taking bisect? of 0.69375 & 0.7125 m X? = (0.69375 + 0.7125) / 2 = 0.703 Q = 0.014 × (20 × 0.703)?/3 / 0.03 × (20 × 0.703)%/3 = 4.95 m3/sec ? The depth will be greater than 0.703 m & less than 0.71 m Ans.

          Sol?
Given that the depth of flow ranges 0.6 m < H < 0.9 m.
? Considering => H = (0.6 + 0.9) / 2 = 0.75 m
Now verify the equation & above consideration
Q = S??? (BH)?/3 / r (B+2H)%/3 => 0.0002??? × (20 × 0.75)?/3 / 0.03 × (20 + 2 × 0.75)%/3 => 5.67 m3/sec
Now, Considering a slightly less depth.
=> (0.6 + 0.75) / 2 = 0.675 m
Q = 0.0002??? (20 × 0.675)?/3 / 0.03 × (20 + 2 × 0.675)%/3 = 4.74 m3/sec
Now, A new depth b/w 0.675 & 0.75 m
Avg of depth will be = (0.675 + 0.75) / 2 = 0.7125 m
Q = 0.0002??? × (20 × 0.7125)?/3 / 0.3 × (20 + 2 × 0.7125)%/3 => 0.014 × 84.5 / 0.03 × 7.55 => 5.22 m3/sec
Now, Taking Avg depth b/w 0.675 & 0.7125 => (0.675 + 0.7125) / 2 = 0.69375
Q = 0.14 × (20 × 0.69375)?/3 / 0.03 × (20 + 2 × 0.69375)%/3 => 4.90 m3/sec
Now Taking bisect? of 0.69375 & 0.7125 m
X? = (0.69375 + 0.7125) / 2 = 0.703
Q = 0.014 × (20 × 0.703)?/3 / 0.03 × (20 × 0.703)%/3 = 4.95 m3/sec
? The depth will be greater than 0.703 m & less than 0.71 m Ans.

Sol?
Given that the depth of flow ranges 0.6 m < H < 0.9 m.
? Considering => H = (0.6 + 0.9) / 2 = 0.75 m
Now verify the equation above consideration
Q = S??? (BH)?/3 / r (B+2H)%/3 => 0.0002??? × (20 × 0.75)?/3 / 0.03 × (20 + 2 × 0.75)%/3 => 5.67 m3/sec
Now, Considering a slightly less depth.
=> (0.6 + 0.75) / 2 = 0.675 m
Q = 0.0002??? (20 × 0.675)?/3 / 0.03 × (20 + 2 × 0.675)%/3 = 4.74 m3/sec
Now, A new depth b/w 0.675 0.75 m
Avg of depth will be = (0.675 + 0.75) / 2 = 0.7125 m
Q = 0.0002??? × (20 × 0.7125)?/3 / 0.3 × (20 + 2 × 0.7125)%/3 => 0.014 × 84.5 / 0.03 × 7.55 => 5.22 m3/sec
Now, Taking Avg depth b/w 0.675 0.7125 => (0.675 + 0.7125) / 2 = 0.69375
Q = 0.14 × (20 × 0.69375)?/3 / 0.03 × (20 + 2 × 0.69375)%/3 => 4.90 m3/sec
Now Taking bisect? of 0.69375 0.7125 m
X? = (0.69375 + 0.7125) / 2 = 0.703
Q = 0.014 × (20 × 0.703)?/3 / 0.03 × (20 × 0.703)%/3 = 4.95 m3/sec
? The depth will be greater than 0.703 m less than 0.71 m Ans.

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