The 3 ? control limits for an np-chart were established at 11.3 and 42.8 using samples of 389 units. The process remains stable. It is decided to decrease the subgroup size to 264 units and to continue monitoring with a np-chart. The new lower np control limit (LCLnp) is 17.7 defective units.
Added by James L.
Close
Step 1
The average number of defective units in the original sample is the midpoint of the control limits, which is: $$ \frac{11.3 + 42.8}{2} = 27.05 $$ The proportion of defective units in the original sample is: $$ p = \frac{27.05}{389} = 0.069537 $$ Show more…
Show all steps
Your feedback will help us improve your experience
Benjamin Densmore and 81 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The 3 σ control limits for an np-chart were established at 11.3 and 42.8 using samples of 389 units. The process remains stable. It is decided to decrease the subgroup size to 264 units and to continue monitoring with a np-chart. The new lower np control limit (LCLnp) is 17.7 defective units.
Adi S.
The 3σ control limits for an np-chart were established at 12.2 and 47.9 using samples of 372 units. The process remains stable. It is decided to decrease the subgroup size to 214 units and to continue monitoring with a np-chart. The new centre np control limit (CLnp) is 5.34 defective units. True False
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD