00:01
Hi, there is a question, we say that the acceleration function in meter per second square and the initial velocity being given as acceleration as a function of time t is 2t plus 5 v when t equal to 0 is minus 6, 0 less than equal to t less than equal to 3 and acceleration is in meter per second square.
00:24
I need to find the velocity at time t, velocity at time t.
00:30
So, first of all, acceleration is dv by dt 2t plus 5.
00:37
Let us separate and solve this differential equation and it is given that when time is 0 velocity is minus 6 and when time is t velocity, let us say v as a function of t.
00:55
So, this is v as a function of t minus 6 equal to 2t square by 2 plus 5t from 0 to t, 2, 2 gets cancelled out.
01:06
So, t square plus 5t minus 0 after plugging in the limits.
01:12
So, velocity at the time t, t square plus 5t plus 6 and meter per second...