The acceleration produced when three forces act on a 0.060-kg object is \(\vec{a} = 3.830\hat{i} + 3.140\hat{j} \text{ m/s}^2\). \(\vec{F}_1 = 14.230\hat{i} + 2.710\hat{j} \text{ N}\) and \(\vec{F}_2 = -4.400\hat{i} + 12.200\hat{j} \text{ N}\) are two of the forces. What is the \(\hat{i}\)-component of the third force? Submit Answer Tries 0/16 What is the \(\hat{j}\)-component of the third force? Submit Answer Tries 0/16
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The net force on the object is equal to the mass of the object multiplied by its acceleration. So we have: F_net = m * a Show more…
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