Question

The area between the function $f(x) = 4 \cdot x + 1$ and the x-axis, between the points $[\frac{-19}{4}, \frac{9}{4}]$ is A = In the box, write 1: at the first row, the expression for the area starting with $\int$( 2: at the second row, subtitutions in the form: (value at upper limit) - (value at lower limit), 3: and at the earliest of the third row, give the solution. The integral is given with the command int(function, mtj, lower bound, upper bound) e.g, $\int_{1}^{2} x + 1 \, dx$

          The area between the function $f(x) = 4 \cdot x + 1$ and the x-axis,
between the points $[\frac{-19}{4}, \frac{9}{4}]$ is
A = 

In the box, write
1: at the first row, the expression for the area starting with $\int$(
2: at the second row, subtitutions in the form: (value at upper limit) -
(value at lower limit),
3: and at the earliest of the third row, give the solution.
The integral is given with the command int(function, mtj, lower
bound, upper bound) e.g, $\int_{1}^{2} x + 1 \, dx$

The area between the function f(x) = 4 · x + 1 and the x-axis,
between the points [(-19)/(4), (9)/(4)] is
A =

In the box, write
1: at the first row, the expression for the area starting with ∫(
2: at the second row, subtitutions in the form: (value at upper limit) -
(value at lower limit),
3: and at the earliest of the third row, give the solution.
The integral is given with the command int(function, mtj, lower
bound, upper bound) e.g, ∫1^2 x + 1 dx

Added by Michael T.

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