00:01
To the students, theory is solving a question in biology.
00:04
As you can see from the question, they've given us a piece of dna segment naming template strand and non -template strand.
00:10
And they place a template strand below.
00:12
And as we know, this non -template strand is also called as folding strand.
00:17
It does not code for anything, but it remains as the structural integrity support for the template strand.
00:23
And the question they have given us is the star marks indicate the start and end points of transcription.
00:28
And we're also asking us what is the resulting mrna sequence and insert start codons and stop corons and underline utrs? so we have to basically transcribe the given dna sequence to mrna.
00:42
So i'll write the answer of cam so that we can contemplate further and therefore here you can see that this is the template strand as they've given us in the question.
00:52
Okay and as you can see i have inserted the star marks of the question but it clearly says, said as it is start and end points of transcription.
01:02
We know that the start point and end points of transcription are called as untranslated regions.
01:09
The start and end point of translation are called as untranslated regions as they do not get transcribed.
01:19
So here we can remove the a and we can remove this t as this t and this g.
01:31
Are both parts of the start and endpoints of transcription.
01:36
Therefore, our final transcribed mrna sequence is uac, g -au, g -au, g -au, and it continues up to g -a.
01:45
We know that the time when is replaced by eural in rna, so i have done the same.
01:50
So therefore, this is our mr -n -e sequence and above is what are template lies.
02:00
And they've also saying us to insert the start codons and stop codons and underlined.
02:05
So if you see the start code on for every dna sequence is aug.
02:11
Okay, since there's no space i'm writing here, the start code on for every dna sequence is aug.
02:20
And this aug is the codon coding for amina acid methion.
02:25
Now if this aug is present anywhere in the middle, then it will quote for vtha.
02:30
Unit but aug at beginning of every mrna sequence will always be the start codon and similarly the stop codon can be any of the three stop codons it can be either uag or it can be either uga or it can be either uaa all of these three codons are stop codons as they do not code for anything so the stop codons can either be this, but the start codon will be meteor and therefore this is our answer for the first quest.
03:09
The second question is asking us, using mrne sequence mark the coronet triplets and identify the number of codons present.
03:17
So to answer this question, let's insert our mrn sequence that we've written above.
03:21
As you can see, this was our mrne sequence and it has a polarity opposite to the template strand, which must be 5 prime it must be 5 prime to 3 prime n and they're saying us to mark the coron triplets so coron triplets is basically variable depending on the reading frames okay the coron triplets is variable depending on our reading frame like we omit the first base path and we start continuing from the second base path then the coronet triplets will be changing but let's assume the first base pad is also included.
04:02
So our first chord -on tripler is uac, then gau, then gau, then g -a -u -u -u -u -u -u -u, then a -c -u -u -u -u, then a -g -g -g -g -a, then a -u -a, then a -u -a, and g -c -a, and then finally we are left with a -a.
04:22
And this a -a is untranslated as they are not forward on.
04:28
The aa is actually untranslated.
04:37
Okay and if we count them we can see that the number of codons present in this dna sequence in this mrna sequence is equal to 13...