The atomic radius of iridium (Ir) is 1.36 Å. The unit cell of the iridium atom corresponds to the Face Centered Cubic (FCC) system. Calculate the density of the iridium atom.
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Step 1
Given: Atomic radius of iridium (Ir) = 1.36 Å For FCC, the relationship between the length of the unit cell (a) and the atomic radius (r) is a = 4√2r Substitute r = 1.36 Å into the equation: a = 4√2 * 1.36 = 3.85 Å Convert 3.85 Å to centimeters: 1 Å = 10^-10 Show more…
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