00:03
In this question, we want to find the density of arridium, given the information about the unit cell.
00:13
So, aridium is a face -centered cubic unit cell.
00:19
So what it looks like is it's going to just be a cube, and then we're going to have atoms on each of the corners, and then on each of the faces we're going to have atoms.
00:37
So in a face -centric cubic unit cell, there are four atoms total.
00:44
So if we zoom in on one of the faces of this unit cell, we will see that it looks like that.
00:54
So the atoms are all touching.
00:56
And if we draw a line to form a right triangle, we see the hypotenuse is equal to 4r, because we go right through the center of the center atom, and then we end up in the center of the atoms on the corners.
01:21
And these atoms are all touching.
01:23
There's no space in between them, so the hypotenuse is 4r, and r is the radius of the atoms.
01:30
Then we can label the size as d or whatever variable we want, and then we can use the pythagorean theorem to solve for d because we know r and d and the sides of the cube are the same because it's a cube.
01:55
So knowing that, we then set up our formulas.
02:00
So d squared plus d squared is going to 4r squared.
02:03
Now we want to solve for d.
02:05
So convert antstroms to pico meters by multiplying by 100.
02:10
Then we will convert that to centimeters, knowing that there are 10 to the 12 piquemeters and 1 meter, there are 100 centimeters and one meter.
02:18
And then we get the length of the radius instead of meters.
02:25
Then we're just going to solve for d.
02:27
So if we solve for that algebraically, plugging in the value for r, we get this as a value of d, the side of the cube...