00:01
The beam ab is supported by roller at a and pin at b.
00:07
If f1 equals 100 kilo newton, f2 is 250 kilo newton and f3 is equal to 120 kilo newton, l1 equals 0 .5 meter, l2 is 2 meter and l3, equals 1 meter the angle theta equals 20 degree then determine the component of force vectors f1 f2 and f3 next the moment of forces moment of forces f1 f3 at point b then the value of vertical and horizontal component of reaction forces at support b and the value of the component of reaction force at point a.
01:32
The component of forces f1 we have f1 cost theta and f1 sine theta substituting the value 100 kilo newton into cost 20 degree is equals to and 100 kilo newton into sine 20 degree this is the x direction force and this is the y direction force for f1 on solving 93 .969 kilo newton in the x direction and for y direction it is minus 34 .202 kilo newton.
02:24
For f2 the component of forces in x direction will be 0 and for y direction it will be equals to negative of f2 this is minus 250 kilo newton.
02:44
For the force vector in x direction again it will be zero and in y direction it is equal to negative of f3 and f3 given is minus 120 kilo newton to find the moment of the force vectors the moment by f1 vector is equals to f1 multiplied by 3 .25 is equal to your f1 is 34 .202 into 3 .25 will give us the value triple 1 .156 kilo -neuton meter.
03:32
Moment generated by force f2 is equals to f2 multiplied by 0 .75 equals f2 given is 250 kilo newton multiplied by 0 .75.
03:48
It will be 187 .5 kilo -neuton meter.
03:56
Moment generated by force vector f3 is equal to f3 into 0, this will be equals to 0 kilo newton meter...