00:02
Hi, from the question it is given that bending moment.
00:06
So first right, what are the things given in the question? so given that bending moment, m of a beam is denoted by d m by d x will be equal to minus w, l minus x.
00:25
Where l and w are constant.
00:30
And we need to determine m in terms of x and also given that m is equal to off of w l squared when x is equal to 0.
01:07
So we need to find m in terms of x.
01:11
Let this be equation number one.
01:14
So first consider equation one from equation one we have d .s.
01:18
Is equal to minus w into l minus x into d x so integrate on both side so we have integral of dm will be equal to minus w since w is a constant term integral of l minus x into d x so integrate this we get m is equal to minus w integral of l minus x d x let u is equal to l minus x d x let us equal to l minus x.
01:49
This implies d u z equal to minus d x substitute these value in the above expression so we get m is equal to minus w integral of u for d x minus d u.
02:04
So this is equal to minus w integral of u du is this minus into minus so this will become plus so we get u squared by 2.
02:15
So this is equal to w into for you substitute l minus x.
02:20
So, l minus x the old square divided by 2...