00:01
So you can say the diagram of the problem.
00:03
So at point b, actually the weight is acting.
00:10
So if the body is here, at b, the weight mg will act towards the center of the path.
00:20
So this mg will supply the centrifugal force and the normal force will be just opposite to this.
00:27
So normal nb will be nothing but mg at the top of the circular force.
00:33
Because it is always perpendicular, i mean the radius is always perpendicular to any point.
00:41
So for the first case, i mean the normal force on the block by the path is mg.
00:49
Because it is mg and so the path will apply the reaction mg to the block.
00:58
If there is the block is here, it is applying a force mg on the path.
01:04
Path vertically downward so the path will apply mg vertically upward so mb will be upg okay now in case of say in case of second part at a as you can see the centricidal force will be in this direction so if the block is here now it's weight is acting vertically downwards mg so the component and this angle will be also theta, i mean 30 degrees...