The body in the figure is pivoted at O, and two forces act on it as shown. If $r_1 = 2.31 \text{ m}$, $r_2 = 2.12 \text{ m}$, $F_1 = 3.53 \text{ N}$, $F_2 = 4.76 \text{ N}$, $\theta_1 = 62.0^\circ$ and $\theta_2 = 62.0^\circ$, what is the net torque about the pivot?
Added by Joy M.
Close
Step 1
In this problem, there are two forces acting on the body: F1 and F2. The distance from the pivot point O to the line of action of F1 is r1, and the distance from the pivot point O to the line of action of F2 is r2. Show more…
Show all steps
Your feedback will help us improve your experience
Donald Albin and 76 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The body in Fig. $10-39$ is pivoted at $O$, and two forces act on it as shown. If $r_{1}=1.30 \mathrm{~m}, r_{2}=2.15 \mathrm{~m}, F_{1}=$ $4.20 \mathrm{~N}, F_{2}=4.90 \mathrm{~N}, \theta_{1}=75.0^{\circ}$ and $\theta_{2}=60.0^{\circ}$, what is the net torque about the pivot?
Pivoted at $O$ The body in Fig. $11-31$ is pivoted at $O$, and two forces act on it as shown. (a) Find an expression for the net torque on the body about the pivot. (b) If $r_{A}$ $=1.30 \mathrm{~m}, r_{B}=2.15 \mathrm{~m}, F_{A}=4.20$ $\mathrm{N}, F_{B}=4.90 \mathrm{~N}, \theta_{A}=75.0^{\circ}$, and $\theta_{B}$ $=60.0^{\circ}$, what is the net torque about the pivot?
The body in the figure is pivoted at O. Three forces act on it in the directions shown: FA = 12.0 N at point A, 9.30 m from O; FB = 11.0 N at point B, 3.90 m from O; and FC = 23.0 N at point C, 2.10 m from O. Taking the clockwise direction to be negative, what is the net torque about O?
Sri K.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD