00:01
The angular speed omega is given to be 3 .3 revolution per minute and this can be converted to radion per second by multiplying it with 2 pi and dividing by 60.
00:18
On calculating we get 0 .345575 radion per second.
00:29
The radius of the ferry wheel is given to be 8 .2 meters.
00:34
And the spear of the car is given to be 16 km per hour and this can be converted to meter per second by multiplying it with thousand and dividing by three sorry three thousand six hundred which gives 4 .444 meter per second and the acceleration of the car is given to be 2 .5 meter per second square.
01:13
Now the velocity of the ferry wheel at the given point is given by its speed multiplied by cost theta i cap plus sine theta j cap.
01:32
The speed of the ferry wheel is given by the product of its angular speed and the radius multiplied by car.
01:45
Cos theta i cap plus sine theta j cap.
01:51
Now substituting the values we get 0 .345575 radion per second multiplied by 8 .2 meters multiplied by cos 36 degrees i cap plus sine 36 degrees j cap.
02:14
On calculating we get 2 2 .292 i cap plus 1 .66561 j cap meter per second.
02:29
Now the velocity of the car with respect to the observer vab is given by va minus vb and va can be written as 4 .44 meter per second i cap and vb is calculated to be 2 .29252 i cap plus 1 .66561 j cap meter per second now on calculating we get 2 .15192 i cap minus 1 .66561 j cap meter per second now on calculating we get 2 .15192 i cap minus 1 .66561 1.
03:20
J cap meter per second...