The car in moves in a straight line such that for a short time its velocity is defined by v = f(t) =(3t^2 + 2t) m/s where t is in second. When t = 0, s = 0. Determine it position (s) and acceleration (a) when t = 3s.
Added by Alvaro C.
Step 1
We can do this by integrating the velocity function with respect to time. ∫v(t) dt = ∫(3t^2 + 2t) dt = t^3 + t^2 + C Given that s = 0 when t = 0, we can solve for C and find that C = 0. So, the position function is s(t) = t^3 + t^2. Now, we can find the Show more…
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