00:01
Hello students in the question we are given dc shunt motor here we have back emf.
00:07
It is equal to 225 volt resistance of shunt.
00:13
It is given as 160 ohms.
00:16
We have line current equal to 7 amperes shunt current.
00:24
It is equal to 1 .5 amperes and here we have stray power losses equal to 118 .5 watt.
00:40
So for part a here we have r major current ia it is equal to line current minus shunt field current.
01:00
So here ia it is equal to 7 amperes minus 1 .5 amperes.
01:06
This comes out to be equal to 5 .5 amperes and here we have applied voltage v.
01:14
It is equal to shunt current into shunt resistance.
01:21
So here this is equal to 1 .5 amperes into 160 ohms.
01:28
This comes out to be equal to 240 volt.
01:33
So here r major resistance ra it is equal to net voltage divided by r major current.
01:58
So here we have formula v minus eb divided by ia.
02:08
So here we get r major resistance.
02:11
It is equal to 240 volt minus 225 volt divided by 5 .5 amperes.
02:20
This comes out to be equal to 15 divided by 5 .5.
02:24
This is equal to 2 .727 ohm.
02:29
We can approximate this as r major resistance.
02:33
It is equal to 2 .73 ohms.
02:39
For part b, we have to find copper loss.
02:42
It is given by formula r major current square into r major resistance.
02:48
So here we have copper loss.
02:53
It is equal to 5 .5 amperes square into 2 .727 ohms.
03:01
Here we get copper loss is equal to 82 .49 watt.
03:12
Now for part c, we have to find output power...