The charge on a parallel plate capacitor varies as q=q.cos2vt. The plates are very large and close together (area = A, separation = d ) , the displacement current through the capacitor will be ?
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The displacement current is given by the rate of change of electric flux through the capacitor. Show more…
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Round 1
The charge on a parallel plate capacitor is varying as $q=q_{0} \sin 2 \pi \cdot n t$ The plates are very large and close together. Neglecting the edge effects, the displacement current through the capacitor is (A) $\frac{q}{\varepsilon_{0} A}$ (B) $\frac{q_{0}}{\varepsilon_{0}} \sin 2 \pi n t$ (C) $2 \pi n q_{0} \cos \pi n t$ (D) $\frac{2 \pi n q_{0}}{\varepsilon_{0}} \cos 2 \pi n t$
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