The charge on a parallel plate capacitor is varying as $q=q_{0} \sin 2 \pi \cdot n t$ The plates are very large and close together. Neglecting the edge effects, the displacement current through the capacitor is
(A) $\frac{q}{\varepsilon_{0} A}$
(B) $\frac{q_{0}}{\varepsilon_{0}} \sin 2 \pi n t$
(C) $2 \pi n q_{0} \cos \pi n t$
(D) $\frac{2 \pi n q_{0}}{\varepsilon_{0}} \cos 2 \pi n t$