00:01
Hello, here we have to solve the following problem.
00:05
The upper portion of the circuit of the wire is fixed and is connected to the voltage of 12 volts.
00:13
The wire of the bottom has a mass of 10 grabs and that's l which is 5 cm long.
00:26
The spring stretches by the distance of half a centimeter under its own weight.
00:38
Under the weight of the wire and when the field is on there is an additional deformation of 0 .30 or 0 .300 centimeters we have to find magnitude of the field.
00:55
Let's solve this problem and first of all we look at the situation when the field is off.
01:06
When the field is off gravity acting on this bottom of the road wire is balanced by the force of the spring.
01:23
Therefore, force of the spring, which is k, delta x0 equals to m0.
01:30
Therefore, k constant of the spring is m0 g over delta x0.
01:52
Let's calculate it...