The combustion of propane is given by the following reaction: C3H8 + 5 O2 → 3 CO2 + 4 H2O The enthalpy of reaction is -2202.0 kJ/mol. How much energy (in joules) will be released if 72.12 grams of propane is burned? (Molar mass of propane = 44.11 g/mol).
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Step 1
12 grams. Given: Molar mass of propane (C3H8) = 44.11 g/mol Mass of propane = 72.12 grams Number of moles = Mass / Molar mass Number of moles = 72.12 g / 44.11 g/mol Number of moles = 1.636 moles Show more…
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C3H8 + 5O2 -> 3CO2 + 4H2O The enthalpy of reaction is -2202.0 kJ/mol. How much energy (in joules) will be released if 96.20 grams of propane is burned? (Molar mass of propane: 44.11 g/mol)
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