The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm-1. Calculate its molar conductivity.
Added by Naval W.
Step 1
Step 1: Recall the formula for calculating molar conductivity: \[ \Lambda_m = \frac{1000 \times \kappa}{c} \] where: - \( \Lambda_m \) = molar conductivity - \( \kappa \) = conductivity in S cm\(^{-1}\) - \( c \) = concentration in mol L\(^{-1}\) Show more…
Show all steps
Your feedback will help us improve your experience
Ravindra Samadiya and 71 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Vivek K.
The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm-1. Calculate its molar conductivity
Meera D.
The molar conductivity of a 0.25 M solution of KCl at 300 K is 100 S cm^2 mol^-1. The conductivity of the solution in S cm^-1.
Ivan K.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD