00:01
In part a of the question we are assigned to the task to calculate activation, energy, the rate constant, that is k1, is given as 1 .3 into 10 ,000 to the power minus 6 second inverse at temperature t1 is equals to 6 .73 kelvin.
00:24
The rate constant k2 is given as 1 .1 into 10 raise to the power minus 5 second inverse at temperature, t1.
00:32
T2 is equal to 703 kelvin.
00:36
We know that ln k2 divided by k1 is equals to ea divided by r, 1 divided by t1 minus 1 divided by t2.
00:49
Now substitute the value into this expression we will get ln 1 .1 into 10x to the power minus 5 divided by 1 .3 into 10x to the power minus 5 divided by 1 .3 into 10x to the power minus 6.
01:03
Is equal to activation energy divided by 8 .314 into 10x to the power minus 3.
01:12
This is the gas constant into 1 divided by 673 minus 1 divided by 703.
01:20
On solving this we will get the value of activation energy that is ea is equal to 280 kilojoule per month.
01:30
This is the value of activation energy.
01:36
And the second part of the question, we are assigned to the task to calculate frequency factor, which is represented by the symbol a at temperature 703 kelvin.
01:53
Now, we know that k is equal to a, e raised to the power minus ea divided by rt...